Supposing that you have a cube with a height that is the square root of its base, and knowing that the cube's volume is 2/3 the sum of its width's two sides, supposing the value of its width would be the hypotenuse of a right triangle, do you know oyashiro-sama?

>>9694160

A basic right triangle has a hypotenuse of x*2^(0.5), where x are the lengths of the legs.

This is where you equation falls apart: there is only one width.

Assuming you mean "non-height" measurements, you multiply this by two (twice its width and length) to get 2x*(2^(0.5)). According to a liberal interpretation of your proposition:

4/3x*(2^(0.5)) = ( x*(2^(0.5)) )^3

1.886x = 2.828x^3

1.886 = 2.828x^2

x (length of a side of the cube) is approximately 0.817.

A basic right triangle has a hypotenuse of x*2^(0.5), where x are the lengths of the legs.

This is where you equation falls apart: there is only one width.

Assuming you mean "non-height" measurements, you multiply this by two (twice its width and length) to get 2x*(2^(0.5)). According to a liberal interpretation of your proposition:

4/3x*(2^(0.5)) = ( x*(2^(0.5)) )^3

1.886x = 2.828x^3

1.886 = 2.828x^2

x (length of a side of the cube) is approximately 0.817.